#!/bin/sh
# shldcc - wrap the IBM compiler to look sort of like a unix compiler
# (for linking shared libraries)
# usage: shldcc [opts] objectfiles -o output
# options:
#     -v	verbose
#

QUIET=1

while [ x"$1" != x ]; do
    case "$1" in
	-o) OUTPUT="$2"; shift;;
	-o*) OUTPUT=`echo "$1" | sed 's/^-o//'`;;
	-v) QUIET=0;;
	-*)
	    echo "$0: unknown option $1" 1>&2
	    exit 1
	;;
	*) FILES="$FILES $1";;
    esac
shift
done

LIB='I:\\ibmcppw\\lib;I:\\ibmcppw\\sdk\\lib'
export LIB

case x"$OUTPUT" in
    x*.dll) ;;
    x) echo "$0: Usage: $0 [options] files -o output" 1>&2; exit 1;;
    *) echo "$0: output file must be a DLL" 1>&2; exti 1;;
esac

MAPFILE=`echo "$OUTPUT" | sed 's/\.dll$/.map/'`
LOGFILE=`echo "$OUTPUT" | sed 's/\.dll$/.log/'`

WINEPATH='I:\\ibmcppw\\bin'
export WINEPATH

# note: you must have ilink354 as ilink.exe, not the latest
# patchlevel, as the latest one apparently doesn't work right in wine.


# /Q+ suppresses the copyright notice

echo '/B"/dll /optf /noe"' > .tmp

if [ $QUIET = 0 ]; then
    echo wine 'I:\\ibmcppw\\bin\\icc.exe' /Ge- @.tmp /Q+ \
	/Fm$MAPFILE /Fe$OUTPUT $FILES '|' tee "$LOGFILE"
fi

(
    wine 'I:\\ibmcppw\\bin\\icc.exe' /Ge- @.tmp /Q+ \
	/Fm$MAPFILE /Fe$OUTPUT $FILES
    echo "@@@Exit $?"
) 2>&1 | tr -d '\r' | tee "$LOGFILE" | (
    if [ $QUIET = 1 ]; then
      #
      # The compiler prints its copyright banner every time you run
      # it, and there's apparently no way to fully suppress this.
      # (That is, I think the /Q+ flag above silences some messages
      # but not all of them.) So, since this is extremely annoying and
      # interferes with development, delete the strings from the
      # output. Obfuscate the regexps slightly, because I want them to
      # be precise (no other messages should be suppressed) but I also
      # don't want to be harassed by source-scanning bots or (perhaps)
      # clueless lawyers that think they're actual IBM copyright
      # notices. I wrote this script; it's not IBM's. (Or Microsoft's,
      # either.)
      #
      # Note that the strings with the first character missing are not
      # an accident. That actually happens.
      #
      sed '
	/^[I][B][M] Librarian for Windows (..) Version 0.00.04 cc_WTC357f $/d
	/^(.) [C]opyright [I][B][M] [C]orporation, 1991, 1996\.$/d
	/^(.) [C]opyright [M]icrosoft [C]orp\., 1988, 1989\.$/d
	/^[L]icensed [M]aterials - [P]roperty of [I][B][M] - [A]ll [R]ights [R]eserved\.$/d

	/^[I][B][M](.) VisualAge(..) for C++ for Windows(.), Version 3\.5$/d
	/^- [L]icensed [M]aterials - Program-[P]roperty of [I][B][M]$/d
	/^(.) [C]opyright [I][B][M] [C]orp. 1991, 1996 - [A]ll [R]ights [R]eserved.$/d

	/^[B][M](.) Linker for Windows(.), %0$/d
	/^ersion 02.01.r2a_WTC354e *$/d
	/^[o]pyright (.) [I][B][M] [C]orporation 1988, 1998\.$/d
	/^[C]opyright (.) [M]icrosoft [C]orp\. 1988, 1989\.$/d
	/^[A]ll [r]ights [r]eserved\.$/d
      '
    else
      cat
    fi
) | awk '
    /^@@@Exit [0-9][0-9]*$/ { exit($2); }

    /^%0$/ { next; }
    /^$/ { next; }
    /%0$/ { sub("%0$", "", $0); printf "%s", $0; needeol=1; next; }
    { print; needeol=0; }
    END { if (needeol) printf "\n"; }

' "q=$QUIET"